Video summary
Binary Search - Leetcode 704 - Python
Main summary
Key takeaways
Main ideas / concepts
-
Binary search problem (LeetCode 704):
- Input: a sorted (ascending) array
numsand a target value. -
Output: return the index of
targetif it exists; otherwise return -1 (The subtitles mention “return one,” but the described solution/code returns -1.) -
Goal: achieve O(log n) time complexity.
- Input: a sorted (ascending) array
-
Core strategy (using two pointers):
- Maintain a search range within the array using two indices:
leftat the start of the range (initially0)rightat the end of the range (initiallylen(nums) - 1)
- Repeatedly check the middle of the current range and eliminate half the remaining candidates based on comparisons.
- Maintain a search range within the array using two indices:
-
Why it’s efficient:
- Each iteration removes about half of the remaining search space.
- For an array size
n, the number of iterations is about log₂(n), yielding O(log n).
Step-by-step algorithm (as described)
-
Initialize
left = 0right = len(nums) - 1
-
Loop condition
- Continue while
left <= right - This guarantees there is still at least one candidate index to check.
- Continue while
-
Within each loop iteration
- Compute the middle index:
mid = (left + right) // 2(integer division)
- Compare:
- If
nums[mid] > target:- Target can only be to the left
- Update:
right = mid - 1
- Else if
nums[mid] < target:- Target can only be to the right
- Update:
left = mid + 1
- Else (equal):
- Return
midimmediately (target found)
- Return
- If
- Compute the middle index:
-
After the loop
- If the loop ends without returning, the target was not found
- Return -1
Important implementation note (overflow-safe mid calculation)
-
Potential bug (in some languages like Java/C++ with 32-bit ints):
- Computing
midas(left + right) // 2can overflow whenleftandrightare large.
- Computing
-
Safer method:
- Compute:
mid = left + (right - left) // 2
- This avoids overflow because
right - leftis non-negative and stays within bounds.
- Compute:
Speakers / sources
- Speaker: Unspecified individual (YouTube channel host/instructor; no name provided in the subtitles).