Video summary
Maths One Shot for SSC CGL 2025 | SSC CGL & CHSL Maths Important Questions By Akshay Sir
Main summary
Key takeaways
Main ideas / lessons (what the speaker teaches)
- Focus on high-frequency Maths topics for SSC/CHSL/NTPC/CGL, especially:
- Simplification, Percentages, Profit-Loss, Simple & Compound Interest
- Time & Work, Speed-Time-Distance, Ratio
- Mixture/Alligation, Number System, LCM/HCF
- Algebra, Trigonometry, Mensuration, Geometry
- Follow a strong core exam strategy:
- Practice expected question patterns
- Use “tricks” for speed
- Do not leave any question
- Adopt a method-first mindset:
- If a question matches a known pattern, use the known transformation
- Don’t start from scratch
- Repeated emphasis on repeatable shortcut rules, often described as:
- “direct trick” / “format”
Detailed methodology / instruction-style content (as presented)
1) Sum of natural numbers/multiples using pattern grouping
Example taught: sum of numbers from 1 to 100 that are multiples of 7.
Method:
- Identify multiples: 7, 14, 21, …, 98
- Use series-sum by grouping/trick
- Treat as a structured arithmetic progression and compute via transformation
2) Adding series of fractions with the same denominator structure
Example taught: compute expressions like 991/7 + 992/7 + … + 996/7
Method:
- Separate integers and fractional part
- Count how many times the integer part repeats (e.g., 99 appears 6 times if there are 6 terms)
- Add integer part using multiplication (e.g., 99×6)
- Add the remaining fraction contribution
3) Time & Work with pairwise work times (LCM-based)
Example taught:
- A + B completes in 18 days
- B + C completes in 27 days
- C + A completes in 54 days
- Find time for 50% of total work
Method (as taught):
- Take LCM of pair-work times:
- LCM(18,27,54) = 54 → interpret it as total work = 54 units
- Convert each pair work to per-day work rates on that total:
- A + B: 54 units in 18 days → 54/18 = 3 units/day
- B + C: 54 units in 27 days → 54/27 = 2 units/day
- C + A: 54 units in 54 days → 1 unit/day
- Infer individual contributions from the overlaps (pair sums correspond to double-counting individuals)
- For 50% completion:
- 50% of 54 = 27 units
- Compute the time taken by the combined effective work rate to produce 27 units (final result stated)
4) Square-root extraction using identity (a^2 + b^2 \pm 2ab)
Example taught: extracting a square root from an expression containing ±2ab
Method:
- Use:
- ((a+b)^2 = a^2 + b^2 + 2ab)
- ((a-b)^2 = a^2 + b^2 - 2ab)
- Match the expression to the correct identity
- Then take the square root accordingly
5) Least number divisible by multiple numbers + perfect square constraint
Example taught: least number divisible by 16, 20, 24 and also a perfect square
Method:
- Compute LCM(16,20,24) (given as 240 in the script)
- Convert prime factorization into even powers only:
- Pair factors to make exponents even
- Multiply remaining unpaired factors to reach the next perfect square
- Perfect-square result stated: 3600
6) Discount on “packs” using effective selling price
Example taught:
- 1 bottle price = ₹240
- 4 bottles pack price = ₹768
- Find % discount on the pack
Method:
- Expected price for 4 bottles if sold individually:
- 240×4 = ₹960
- Actual pack price = ₹768
- Discount = 960 − 768 = ₹192
- % discount = (192/960)×100 = 20% (final stated)
7) Speed ratio vs time ratio (inverse proportion)
Method taught:
- If speeds are in ratio (v_1:v_2:v_3) and distances are the same:
- time ratio = 1/v₁ : 1/v₂ : 1/v₃
- Warning:
- Don’t treat “inverse” as merely “opposite” casually
- You must take the reciprocal
8) Tricky series / roots involving “carry/next step”
- Several mistake-prone series and root problems were taught with warnings like:
- Be careful when adding numbers inside root and later removing root
- Many steps were framed as common exam pitfalls
9) Profit/Loss questions like “18 articles for ₹1680”
Method taught:
- Profit = Selling Price − Cost Price
- If the framing implies equivalence like:
- profit on 18 items = CP of 3 items
- Interpret using:
- SP(18) − CP(18) linked to CP(3)
- Use ratio-based CP per item:
- CP(18) = (CP per item)×18
- Final CP per item stated: ₹80 (option A mentioned)
10) Percentage error questions
Method taught:
- If someone uses a wrong reciprocal factor:
- Compute wrong result vs correct result difference
- Convert that difference into:
- % of the correct value
11) Mixtures / spirits concentration using unit multiplication
Example taught:
- 4 liters of 80% spirit + 6 liters of 50% spirit
- Find % spirit in the mixture
Method:
- Convert each component into spirit units (fraction × liters)
- Total spirit proportion:
- Spirit amount = (fraction)×(liters)
- Percentage in final mixture:
- (total spirit / total liters)×100
- Final stated as: 46%
12) Successive discounts equivalence
Example taught: 30% then 20% then 10% successive discounts
Method:
- Convert each discount to the payable multiplier:
- After 30%: pay 70% = 7/10
- After 20%: pay 80% = 4/5
- After 10%: pay 90% = 9/10
- Multiply payable fractions
- Total discount = 1 − payable fraction
- Final stated effective discount: 49.6%
13) Average via “assumed average” / shifting method
Example taught: boys avg 62 kg, girls avg 55 kg with ratio 3:2
Method:
- Choose an assumed average (often the lower average)
- Compute extra over assumed average:
- extra = (actual avg − assumed avg)
- Distribute extra across population by ratio
- Convert back to total average
- Final stated average: 59.2 kg
14) Alternate work / alternating days using LCM and “tasks per day”
Method taught:
- Determine total work per LCM of work rates
- For alternating workers:
- compute work done by the worker who works on a day
- skip the next day for the other worker
- Often reduces to:
- tasks done in one full cycle = A’s work on A-days + B’s work on B-days
- Final stated result for a specific question: 16 days (option B mentioned)
15) Compound interest shortcut using consecutive years
Method taught:
- Use interest behavior over consecutive years
- When amounts at years 3 and 4 are known:
- scale via constant year-over-year increase in compound comparisons
- Use proportionality to extend to 100
- Example results mentioned include:
- interest rate 5% and 12.5% (as stated in different places)
16) LCM trick for powers
Method taught:
- For expressions like:
- 4^12, 4^18, 4^36, 4^24
- If asked for LCM:
- LCM relates to the maximum power handling (as clarified by the speaker)
- Speaker also corrects misconceptions about “smallest vs greatest” power
17) Prime counting between ranges by splitting known primes
Method taught:
- Use known counts up to 50 and 100:
- primes 1–50 = 15
- primes 50–100 = 10 (as referenced)
- Compute total primes in 1–100 by summation and options
- Final stated option: A
Overall structure of the session
- Starts with:
- topic list + schedule + exam relevance
- Then a long sequence of SSC-oriented questions
- For each question:
- identify the pattern
- apply a direct trick / standard identity
- select the final option and emphasize conceptual clarity
- Ends with promotional guidance about joining Adda247 packs using code Y170, plus reminders to revise with PDFs and study plans.
Speakers / sources featured
- Akshay Awasthi / Akshay Sir (main teacher)
- SSC Adda247 (channel/platform referenced)
- Students/participants (referred to frequently as characters/learners, e.g., “kids”, “students”, names used for question context)
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