Summary of "KULIAH STATISTIK - ANALISIS KORELASI"

Main ideas and concepts

Direction examples

Strength of relationship (rule of thumb)

(Strength depends on the magnitude of the correlation coefficient.)

Types of correlation discussed

Methodology / step-by-step instructions

A) Pearson Product Moment correlation (interval/ratio data)

Used when:

Variables/notations mentioned:

Formula (as described):

[ r = \dfrac{n\Sigma XY - (\Sigma X)(\Sigma Y)}{\sqrt{\left[n\Sigma X^2 - (\Sigma X)^2\right]\left[n\Sigma Y^2 - (\Sigma Y)^2\right]}} ]

Example described: sleep length vs emotional stability

  1. Set hypotheses
    • H0 (null): no relationship between sleep length and emotional stability (often described as “negative/no relationship”).
    • H1 (alternative): there is a relationship.
  2. Compute needed sums from the data
    • Calculate: ( \Sigma X ), ( \Sigma Y ), ( \Sigma XY ), ( \Sigma X^2 ), ( \Sigma Y^2 )
    • Determine n (number of observations).
  3. Substitute into the Pearson formula to get r-count
    • The example yields roughly r-count = 0.91 (stated as “0.913”/similar due to subtitle errors).
  4. Decision rule using r-table
    • If r-count ≤ r-tableH0 accepted
    • If r-count > r-tableH0 rejected
  5. Determine r-table
    • Alpha given: α = 0.05
    • Degrees of freedom mentioned as df = n − 2
    • r-table obtained around 0.63 (subtitle contains some typos; the intended process is comparison with the table value).
  6. Conclusion
    • Because r-count > r-table, the conclusion is:
    • Positive relationship between sleep length and emotional stability.

Six steps were explicitly mentioned as the completion structure for Pearson analysis.


B) Spearman Rank correlation (ordinal data)

Used when:

Formula (as described):

[ \rho = 1 - \dfrac{6\Sigma d^2}{n(n^2 - 1)} ]

Example described: start exam scores vs research methodology exam scores

  1. Set hypotheses
    • H0: no relationship between exam results.
    • H1: there is a relationship.
  2. Rank the data (from smallest to largest)
    • Assign ranks to X values and Y values.
    • Ties are handled by using an average rank approach:
      • If a value repeats (e.g., two equal scores), assign the mean of the ranks those positions would occupy.
  3. Compute rank differences
    • For each pair: ( d = \text{rank}_X - \text{rank}_Y )
    • Then compute
  4. Calculate Spearman correlation
    • Substitute into the Spearman formula using n and Σd²
    • Example yields r-count ≈ 0.854 (subtitle text shows “0.8 54”).
  5. Determine criteria / r-table
    • Uses α = 0.05
    • Degrees of freedom approach mentioned similarly to Pearson (subtitle states df = n − 2, then references the table).
    • r-table obtained around 0.648 (subtitle includes minor typos).
  6. Conclusion
    • Since r-count > r-table:
    • H0 is rejected
    • Conclude a positive relationship between the two exam results.

Overall lessons conveyed

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Educational


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