Summary of Molarity, Molality, Volume & Mass Percent, Mole Fraction & Density - Solution Concentration Problems
Summary of Video:
"Molarity, Molality, Volume & Mass Percent, Mole Fraction & Density - Solution Concentration Problems"
Main Concepts and Definitions:
- Solution Components:
- Solute: Substance being dissolved (e.g., Sodium Chloride).
- Solvent: Substance doing the dissolving (e.g., water).
- Solution: Solute + Solvent combined.
- Concentration Units and Formulas:
- Mass Percent (%)
Mass % = (mass of solute / mass of solution) × 100
- Volume Percent (v/v %)
Volume % = (volume of solute / volume of solution) × 100
- Mole Fraction (X):
For substance A in a mixture:
XA = moles of A / total moles in solution
- Molarity (M):
M = moles of solute / liters of solution
Volume must be in liters. - Molality (m):
m = moles of solute / kilograms of solvent
Note: Molality uses mass of solvent, not solution. - Density (ρ):
ρ = mass / volume
Common units: g/mL or g/cm³ (1 mL = 1 cm³).
Useful conversions:- 1 L = 1000 mL
- 1 kg = 1000 g
- Mass Percent (%)
Important Distinctions:
- Molarity vs Molality:
Molarity depends on volume of entire solution (solute + solvent).
Molality depends on mass of solvent only. - Solute vs Solvent in Mixed Solvent Systems:
If both substances can act as solvents (e.g., Methanol and water), the solute is usually the component in lesser quantity or as specified by the problem.
Step-by-Step Problem-Solving Methodology:
- Identify solute and solvent.
- Use the correct formula based on the concentration unit asked.
- Convert units as necessary:
- Calculate total mass or volume of solution if not given (solute + solvent).
- Use Density to convert between mass and volume if needed.
- Plug values into formulas and solve.
Example Problems and Solutions:
- Mass Percent of NaCl:
Given 15 g NaCl + 225 g water → total solution = 240 g.
Mass % NaCl = (15/240) × 100 = 6.25%. - Volume Percent of Methanol and Mass Percent of Water:
Methanol volume = 25 mL, Water volume = 150 mL → solution volume = 175 mL.
Volume % Methanol = (25/175) × 100 = 14%.
Use Density to find mass:
- Methanol mass = 25 mL × 0.792 g/mL = 19.8 g
- Water mass = 150 mL × 1 g/mL = 150 g
Total mass = 169.8 g
Mass % water = (150/169.8) × 100 = 88.3%. - Mole Fraction of KCl:
2 moles KCl + 8 moles water → total moles = 10.
Mole Fraction KCl = 2/10 = 0.2. - Mole Fraction of NaF:
Convert 25 g NaF to moles:
- Molar mass NaF ≈ 42 g/mol → 25/42 = 0.595 moles.
Convert 200 g water to moles:
- Molar mass H₂O ≈ 18 g/mol → 200/18 = 11.1 moles.
Mole Fraction NaF = 0.595 / (0.595 + 11.1) ≈ 0.
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